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Notice that there are four sets of 8 bits (1 or 0), which makes up the 32 bits (8 4 sets) of an IP address Let s take a look at how you can determine the binary representation of an octet The values of the 8 bits within the octet are shown in Table 4-3 Looking at Table 4-3, you can see that the first bit in an octet (far right) has a decimal value of 1, the second bit has a decimal value of 2, the third bit has a decimal value of 4, and the values keep doubling with each additional bit You can also see that the eighth bit has a decimal value of 128 The first bit is known as the least significant bit or low-order bit, while the eighth bit is known as the most significant bit or high-order bit To calculate the binary value of an octet with a decimal number such as 192, you need to enable, or turn on, the bits that will add up to the number of 192, as shown in Table 4-4 Notice that the foregoing table has bit eight and bit seven turned on to give you a value of 128 + 64, which equals 192 The remaining bits will take an off state, which means they are not included in the calculation A bit that has an on state takes a 1, and an off state takes a 0 So the combination of 8 bits to make the number 192 would be 11000000 Now that you know how to convert a decimal value to binary and a binary value to decimal, try out Exercise 4-2 before moving on to the section on address classes



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A number of special sequences occur repeatedly in our work We now collect several of them for easy reference Theorem 123 Let s be a real number 1 If s < 0 then the sequence { j s } converges to 0 j=1 2 If s > 0 then the sequence { j s } diverges j=1 3 If s = 0 then the sequence { j s } is just the constant sequence 1, 1, 1, j=1 and converges to 1 Theorem 124 is a companion to Theorem 123 In Theorem 123 the j s are the base of the exponential, while in Theorem 124 we have j playing the role of the exponent Theorem 124 Let t be a real number 1 If |t| < 1 then {t j } converges to 0 j=1 2 If |t| > 1 then {t j } diverges j=1





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A is correct Omnidirectional antennas are best for coverage purposes such as covering an indoor area or an outdoor area for access by devices B, C, and D are incorrect Semidirectional and patch/panel antennas are used for very short bridge links or to cover an area in one direction Highly directional antennas are best for bridge links

tabLe 4-3

3 If t = 1 then {t j } is the constant sequence 1, 1, 1, which converges j=1 to 1 4 If t = 1 then {t j } diverges j=1 EXAMPLE 1218 Calculate lim j 3/2 + 2 j 2 4 j2

4:

8 128

7 64

7 What kind of antenna is mostly used in outdoor bridge links A Omnidirectional B Semidirectional C Patch/panel D Highly directional

Solution:

6 32

D is correct Highly directional antennas are best for outdoor bridge links A, B, and C are incorrect Omnidirectional antennas are best for coverage purposes such as covering an indoor area or an outdoor area for access by devices Semidirectional and patch/ panel antennas are used for very short bridge links or to cover an area in one direction

5 16

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We use some algebraic manipulations to rewrite our limit as lim j 3/2 2 j2 + lim j 4 j 2 4 j2 = 1 1 1 + lim lim 4 j j 1/2 j 2

8 What is the IEEE standard for lightning arrestor response time A >8 s B <8 s C >16 s D <12 s

tabLe 4-4

B is correct The IEEE standard is <8 s A, C, and D are incorrect These answers are incorrect, as they reflect improper response times

6 32

By Theorem 123 this last line equals 1 1 1 0+ = 4 2 2 EXAMPLE 1219 Calculate 2j + 3j j 4j lim Solution: We multiply the numerator and denominator by 4 j and simplify to obtain that our limit equals 2 j 4 j + 3 j 4 j (1/2) j + (3/4) j = lim j j 4 j 4 j 1 lim = lim Now by Theorem 124(1) this equals 0+0=0

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