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count = 100; /* line 1 */ sample = i / 22 * (c-10); /* line 2 */ printf(''This is an expression"); /* line 3 */

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Let's look more closely at each of these expression statements In C, the equal sign is an assignment operator C does not treat the assignment operation the way a language such as BASIC would, for example In BASIC, the value produced by the right side of the equal sign is assigned to the variable on the left But, and this is important, in BASIC, the entire statement does not have a value In C, the equal sign is an assignment operator, and the value produced by the assignment operation is equal to that produced by the right side of the expression Therefore, an assignment statement is actually an assignment expression in C; because it is an expression, it has a value This is why it is legal to write expressions such as the following:





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EXAMPLE 1-1 The charge in a wire is known to be q(t) = 3t 2 6 C Find the current SOLUTION Using (13), we have i(t) = dq d = (3t 2 6) = 6t A dt dt

Page 721 a = b = c =: 100; printf(''%d", a=4+5);

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The reason these work in C is that an assignment is an operation that produces a value Line 2 of the sample expressions shows a more complex assignment In line 3, printf( ) is called to output a string In C, all non-void functions return values, whether explicitly specified or not Thus, a non-void function call is an expression that returns a value whether the value is actually assigned to something or not Calling a void function also constitutes an expression It is just that the outcome of the expression is void Evaluating Expressions Before we can develop code that will correctly evaluate C expressions, you need to understand in more formal terms how expressions are defined In virtually all computer languages, expressions are defined recursively using a set of production rules The Little C interpreter supports the following operations: +, *, /, %, =, the relational operators (<, = =, >, and so forth), and parentheses , Therefore, we can use these production rules to define Little C expressions:

Here, rel-op refers to any of C's relational operators The terms lvalue and rvalue refer to objects that can occur on the left side and right side of an assignment statement, respectively One thing that you should be aware of is that the precedence of the operators is built into the production rules The higher the precedence, the farther down the list the operator will be To see how these rules work, let's evaluate this C expression:

EXAMPLE 1-2 Find the current that corresponds to each of the following functions of charge: (a) q(t) = 10 cos 170 t mC (b) q(t) = e 2t sin t C (c) q(t) = 4e t + 3e5t C SOLUTION In each case, we apply (13) paying special attention to the units In (a), we have q(t) = 10 cos 170 t mC Since the charge is measured in millicoulombs

195 196 197 198 198 199 200 202 203 203 204

count = 10 - 5 * 3;

First, we apply rule 1, which dissects the expression into these three parts:

I = I1 + I2 + I3 + + In Using Ohm s law, we obtain an equivalent or total conductance G T I = I1 + I2 + I3 + + In Vs Vs Vs Vs = + + + + R1 R2 R3 Rn = Vs 1 1 1 1 + + + + R1 R2 R3 Rn = Vs G T

Since there are no relational operators in the ''rvalue" part of the subexpression, the "term" production rule is invoked:

Next, we must begin moving back up the rules to compute the value of the expression First, we multiply 5*3, which yields 15 Next, we subtract that value from 10, yielding Finally, this value 5 is assigned to count and is also the value of the entire expression The first thing we need to do to create the Little C interpreter is to construct the computerized equivalent of the expression evaluation we just performed in our minds The Expression Parser

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How To Open PDF File In New Tab In MVC Using C# - C# Corner
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