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Duration: 6:33 Posted: Aug 16, 2018

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The latest installers can be downloaded here: tesseract - ocr -w32- setup -v5.0.0- alpha.20190708. exe (32 bit) and ... 2017-06-02 Update Tesseract 3.05.01 .

Next, swap the elements that i and j are indexing, as shown in Figure 914 The scan continues, with i stopping at large element 9 and j stopping at small element 3 However, at this point i and j have crossed positions in the array Consequently, a swap would be useless Hence Figure 915 shows that the item being accessed by j is already correctly placed and should not move Figure 915 shows that all but two items are correctly placed Wouldn't it be nice if we could just swap them and be done Well, we can All we need to do is swap the element in position i and the element in the last cell (the pivot), as shown in Figure 916 The element that i is indexing clearly is large, so moving it to the last position is fine Note that the partitioning algorithm requires no extra memory and that each element is compared exactly once with the pivot When the code is written, this approach translates to a very tight inner loop



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Once you ve changed the bindings for each of the controls, you have a fully functional template part that you can use in any form template But before you can reuse this component in other form templates, you have to save it In terms of what you do, saving a template part is no different than saving a form template However, when you save, InfoPath will give the template part the xtp extension instead of the xsn extension used for form templates This will be important later when you try to locate template parts to reuse When you save the template part, the name you give the le will be the name you ll use when you install the template part into your Controls task pane, which we ll show you how to do next You ve created your rst template part, so let s put it to use (In the last chapter, you learned about publishing form templates You don t actually publish template parts as you do form templates Saving a template part is analogous to publishing it in this case)

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One important detail that we must consider is how to handle keys that are equal to the pivot Should i stop when it encounters a key equal to the pivot, and should j stop when it encounters a key equal to the pivot Counters i and j should do the same thing; otherwise, the partitioning step is biased For instance, if i stops and j does not, all keys that are equal to the pivot wind up on the right-hand side Let us consider the case in which all elements in the array are identical If both i and j stop, many swaps will occur between identical elements Although these actions seem useless, the positive effect is that i and j cross in the middle, so when the pivot is replaced the partition creates two nearly equal subsets Thus the best-case analysis applies, and the running time is O(N log N) If neither i nor j stops, then i winds up at the last position (assuming of course that it does stop at the boundary), and no swaps are performed This result seems great until we realize that the pivot is then placed as the last element because that is the last cell that i touches The result is widely uneven subsets and a running time that matches the worst-case bound of O(N2)The effect is the same as using the first element as a pivot for presorted input: It takes quadratic time to do nothing We conclude that doing the unnecessary swaps and creating even subsets is better than risking widely uneven subsets Therefore we have both i and j stop if they encounter an element equal to the pivot This action turns out to be the only one of the four possibilities that does not take quadratic time for this input At first glance, worrying about an array of identical elements may seem silly After all, why would anyone want to sort 5000 identical elements However, recall that quicksort is recursive Suppose that there are 100,000 elements, of which 5000 are identical Eventually quicksort could make the recursive call on only the 5000 identical elements Then, ensuring that 5000 identical elements can be sorted efficiently really is important.

Once you have a template part whether you created it yourself as we just did or you are reusing one created by somebody else you can add it to your Controls task pane so that you can use it just like any of the built-in InfoPath controls Let s look at how you can install template parts so they can be inserted into your form templates

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