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the process of lling out forms, the Design a Form Template dialog does the same for designing forms From this dialog, you can choose what type of form to design and the data source for your form design (The different types of form designs will be discussed in more detail throughout this book Data sources will be discussed further in 3) From the Design a Form Template dialog, you can also choose to customize one of the sample form templates installed with InfoPath or to download form templates from Of ce Online From this dialog you can also import a form from another application or open a recently used form template With InfoPath 2007, you can import forms from Word or Excel or download other importers from third-party vendors (Form importers are discussed in more detail in 21) As you can see, the Design a Form Template dialog is extremely useful for managing your form templates



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Once you design a form in InfoPath 2007, you might next notice the new controls in the Controls task pane Again, based on customer feedback, InfoPath 2007 added new controls the Combo Box, the Horizontal Repeating Table, the Multiple-Selection List Box, and the Horizontal Region which will all be discussed in s 2 and 4 However, the most exciting addition in terms of controls is the ability to create custom controls with no code InfoPath template parts allow you to create custom controls that are aggregates of existing controls already built into the InfoPath design mode In addition, you can add rules, calculations, data validation, and even secondary data sources to template parts you design, thus creating reusable components with no code required (Template parts are discussed in detail in 10) Another appealing addition to InfoPath 2007 is integration with Outlook InfoPath e-mail forms, as the feature is called, enables users to ll out forms in the body of an e-mail instead of having to open the InfoPath client application InfoPath s deeper integration in Outlook will be discussed in detail in 13 Some of the other additions to the InfoPath client application are not as obvious Many performance improvements enhance the usability of

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Big-Oh result, so once we have found a dominant term, we can ignore lower order terms and leading constants The running time of the algorithm is entirely dominated by the innermost for loop in lines 14 and 15 Four expressions there are repeatedly executed:

1 the initialization k = i, 2 the test k <= j , 3 the increment thissum += a [ k 1, and 4 the adjustment k++

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a rule, and then click the Add Action button This opens the dialog shown in Figure 518 Next, choose the default action, Show a dialog box message, and type in the text Hello, InfoPath! When you ll out the form and click the Button control, a dialog box displays your message That s how easy it is to create a rule to show a message to your users (This sample is called RulesSimpleExample)

The number of times that expression 3 is executed makes it the dominant term among the four expressjons Note that each initialization is accompanied by at least one test We are ignoring constants, so we may disregard the cost of the initializations; the initializations cannot be the single dominating cost of the algorithm Because the test given by expression 2 is unsuccessful

W - ~ l ~ o r i t hAnalysis rn exactly once per loop, the number of unsuccessful tests performed by expression 2 exactly equals the number of initializations Consequently, it is not dominant The number of successful tests at expression 2, the number of increments performed by expression 3 and the number of adjustments at expression 4 are identical Thus the number of increments (ie, the number of times that line 15 is executed) is a dominant measure of the work performed in the innermost loop The number of times line 15 is executed exactly equals the number of ordered triplets ( i , j k) that satisfy I I i I k I j I N2 The reason is that the index i runs over the entire array, 1 runs from i to the end of the array, and k runs from i to j A quick and dirty estimate is that the number of triplets is somewhat less than N x N x N, or N3, because i, j, and k can each assume one of N values The additional restriction i I k Ij reduces this number A precise calculation is somewhat difficult to obtain and is performed in Theorem 61 The most important part of Theorem 61 is not the proof, but rather the result There are two ways to evaluate the number of triplets One is to I = I We could evaluate this sum inside out evaluate the sum (see Exercise 69) Instead, we will use an alternative

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