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The problems in this section, as well as the implementation of the hash table data structure ( 20), require the use of the C++ % operator The % operator, denoted as operator%,computes the remainder of two integral types3 For example, 13 %lo evaluates to 3, as does 3 %lo,and 2 3 %lo When we compute the remainder of a division by 10, the possible results range from 0 to 9 This range makes operator% useful for generating small integers If two numbers A and B give the same remainder when divided by N, we say that they are congruent modulo N, written as A = B (mod N) In this case, it must be true that N divides A - B Furthermore, the converse is true: If N divides A - B, then A = B (mod N) Because there are only N possible remainders-0, I , , N - 1- we say that the integers are divided into congruence classes modulo N In other words, every integer can be placed in one of N classes, and those in the same class are congruent to each other, modulo N We use three important theorems in our algorithms (we leave the proof of these facts as Exercise 810) 1 I f A = B ( m o d N ) , t h e n f o r a n y C , A + C = B + C ( m o d N ) 2 If A = B (mod N), then for any D, AD = BD(mod N) 3 If A = B (mod N), then for any positive R AP = BP(mod N) These theorems allow certain calculations to be done with less effort For Because this instance, suppose that we want to know the last digit in 33335555 number has more than 15,000 digits, it is expensive to compute the answer directly However, what we want is to determine 33335555(mod10) AS 3333 = 3(mod lo), we need only to compute 35S55(mod 10) AS 34 = 81, we know that 34 = 1 (mod lo), and raising both sides to the power of 1388 tells us that 35552 = l(mod 10) If we multiply both sides by 33 = 27, we obtain 35555 27 = = 7(mod lo), thereby completing the calculation.



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public: Rectangle( double len = 00, double wid = 00 ) : Shape( "rectangle" ) , length( len ) , width( wid double area( ) const { return length * width; } private: double length; double width;





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The key in this example is the xsd:any schema construct This is not speci c to InfoPath per se but is understood in XML to mean anything can go in this place If you have an existing schema where you want parts to be open for editing in design mode, you can hand-edit the schema in a basic text editor Add the xsd:any element within each compositor you want to enable editing: xsd:sequence, xsd:choice, or xsd:all Actually, the above example will allow for anything except new attributes XML Schema always segregates elements and attributes, hence the nuance To also open the schema for attributes, you need to add the following within the xsd:complexType node (outside of the compositor):

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derived from ShapeThis derivation is done exactly like all the others In implementing these classes, we must 1 provide a new constructor; 2 examine each virtual function to decide whether we are willing to accept its defaults (for each virtual function whose defaults we do not like, we must write a new definition); 3 write a definition for each pure virtual function; and 4 write additional member functions if appropriate For each class, we provide a simple constructor that allows initialization with basic dimensions ieg, radius f i r circles and side lengths for rectangles and squares) We first initialize the inherited portion by calling the base ciass initializer Each class is required to provide an area method because Shape has declared that it is an abstract method If the area method is not provided for some class, an error will be detected at compile time The reason is that, if an implementation of area is missing, a derived class will itself be abstract Note that square can inherit the area method from Rectangle, so it does not provide a redefinition Note also that its name internally is now

We will not discuss the speci cs of the xsd:any or xsd:anyAttribute nodes as that conversation is schema-speci c and can be found on the W3 Schools Web site (referenced in the Appendix) For InfoPath purposes, even expert schema hackers don t need to know more than what we ve presented in this conversation about enabling the data source for editing

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We re going to take a step back from data source details and see how designing your data source can affect which controls you can use and even

We can only declare arrays Of pointersto base classes because the size of the base class is usually smaller than the size of the derived class It can never be larger

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