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In a searchable PDF, text is recognized using Optical Character Recognition ( OCR ) ... Scan 2 OCR Component (OS X) is installed automatically when you install  ...

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jTessBoxEditor is a box editor and trainer for Tesseract OCR , providing editing of box ... The training process can also be automated using train.ps1 , a Windows  ...

The next chapter finishes the coverage of the concepts behind building data-bound Windows Forms applications with a discussion of validation and error handlingtwo things that are key to building rich and robust data applications that do what the user expects them to do It discusses both the built-in mechanisms for validation and error handling in the Windows Forms controls, and how to supplement what is provided to save repetition in writing your validation and error-handling code

source for this example (This sample, ExpenseTotalCalculation, is included with the samples for this chapter on the book s Web site)



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After N multiplications, r e s u l t is the answer that we are looking for However, doing N multiplications is impractical if N is a 100-digit HugeInt In fact, if N is 1,000,000,000, it is impractical on all but the fastest machines A faster algorithm is based on the following observation That is, if N is even then





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(Recall that LXJ is the largest integer that is smaller than or equal to X) As before, to perform modular exponentiation, we apply a % after every multiplication The recursive algorithm shown in Figure 816 represents a direct implementation of this strategy Lines 9 and 10 handle the base case: X0 is I , by definition4 At line 12, we make a recursive call based on the identity stated in the preceding paragraph If N is even, this call computes the desired answer; if N is odd, we need to multiply by an extra X (and use o p e r a t o r % )

Notice in Figure 48 that we added a footer row to the table You can add a footer row by using the Display tab of the properties dialog for the Repeating Table In the second column of the footer row, we re going to add an Expression Box control that will be used to calculate the sum of all the ExpenseCost elds When inserting the Expression Box, we click on the Edit Formula button, then click on the Insert Function button, and then

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4 We define 00 = 1 for the purposes of this algorithm We also assume that N is nonnegative and P is positive

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This algorithm is faster than the simple algorithm proposed earlier If Exponentiation can M(N) is the number of multiplications used by p o w e r , we have M ( N ) I be done in logarithmic number ~ 4 ~ 1 + 2 The reason is that if N is even, we perform one multiplication, of multiplications 2 1 plus those done recursively, and that if N is odd, we perform two multiplications, plus those done recursively Because M(0) = 0, we can show that M(N) < 2 log N The logarithmic factor can be obtained without direct calculation by application of the halving principle (see Section 65) which tells us the number of recursive invocations of power Moreover, an average value of M(N) is (312)log N, as in each recursive step N is equally likely to be even or odd If N is a 100-digit number, in the worst case only about 665 multiplications (and typically only 500 on average) are needed A C++ note: H u g e I n t s are passed by constant reference to avoid the Do not over optimize copy However we return by copy We could attempt to avoid these exces- You are likely to break your program sive copies, but doing so is not worth the effort The reason is that, for each return, we know we have done a multiplication and mod operation, and the costs of these operations greatly exceed the overhead of the copy Thus optimizing by attempting to use reference return values or global variables is not likely to achieve any significant time improvements

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