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Just as the freezing point of a solution of a nonvolatile solute is always lower than that of the pure solvent, the boiling point of a solution is always higher than the solvent s Again, only the number of solute particles affects the boiling point The mathematical relationship is similar to the one for the freezing-point depression above and is Tb = iKb molality where Tb is the number of degrees the boiling point has been elevated (the difference between the boiling point of the pure solvent and the solution); Kb is the boiling-point elevation constant; the molality is the molality of the solute; and i is the van t Hoff factor You can calculate a solution s boiling point if you know the molality of the solution If you know the amount of the boiling-point elevation and the molality of the solution, you can calculate the value of the van t Hoff factor, i For example, determine the boiling point of a solution prepared by adding 1500 g of 1 NaCl to 2500 g water (Kb = 0512 K kg mol )

3 1 3 2 3 3 The answer is C Clearance units are volume per time, not mass per time The answer is lower Metabolic clearance rate includes all routes of elimination; its value is the renal clearance plus any others The answer is C CIn 5 UInV/P In When P In increases, there is no change in CIn because UIn rises by an identical amount In other words, the mass of inulin filtered and excreted increases, but the volume of plasma supplying this inulin (ie, completely cleared of inulin) is unaltered Substance A could be (1) poorly filtered at the glomerulus, (2) taken up and degraded by the tubular epithelium, or (3) reabsorbed and returned to the blood

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1 mole NaC l 15 00g NaCl 5844 g NaC l 1 T = iK bm = 2(0512 K kg mol ) 250 0 g 1 kg 1000 g =105K T bp =(37315 +105)K = 37420 K (=10105 C)

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A 100 molal aqueous solution of trichloroacetic acid (CCl3COOH) is heated to the boiling point The solution has a boiling point of 10018 C -1 Determine the van t Hoff factor for trichloroacetic acid (Kb for water = 0512 K kg mol ) T = (10118 10000) = 018 C = 018 K i = T /Kbm = 018 K/(0512 K kg mol-1)(100 mol kg-1) = 035 A common mistake is the assumption that the van t Hoff factor must be a whole number This is true only for strong electrolytes at very low concentrations

Answers to study Questions / 203

kinds of PDUs that will flow in such a network; Figure 5-7 does the same for a VoMPLS design As noted, an area that will require attention is MPLS/IP header compression If voice frames are transmitted using the normal RTP/UDP/IP stack, then for each voice frame6 G729A voice frame RTP header UDP header IP header Total 20 bytes 12 bytes 8 bytes 20 bytes 60 bytes a transmission efficiency of 33 percent

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If you were to place a solution and a pure solvent in the same container but separate them by a semipermeable membrane (which allows the passage of some molecules, but not all particles) you would observe that the level of the solvent side would decrease while the solution side would increase This indicates that the solvent molecules are passing through the semipermeable membrane, a process called osmosis Eventually the system would reach equilibrium, and the difference in levels would remain constant The difference in the two levels is related to the osmotic pressure In fact, one could exert a pressure on the solution side exceeding the osmotic pressure, and solvent molecules could be forced back through the semipermeable membrane into the solvent side This process is called reverse osmosis and is the basis of the desalination of seawater for drinking purposes These processes are shown in Figure 131

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PDU (example) (data plane)

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