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Figure 6-6: Segmentation into broadcast domains So the job of Boolean ANDing is to determine whether the host can just broadcast to reach the other host, or send the packet to a router instead Remember, however, that a MAC address is still required If the host can't broadcast for the MAC address of a remote host, how does it get its MAC address Easy It doesn't It uses the router's MAC address instead If a host determines that the host it is trying to reach is on a different network, it sends the packet to a router that is likely to reach the remote network Typically, this router is the host's default gateway (This router could also be one listed in the host's routing table, but we will discuss that further in 22) A default gateway is the IP device to which a host sends a packet when it doesn't know where else to send the packet When it sends the packet to the default gateway, it uses the default gateway's MAC address as the destination MAC address rather than the remote host's, but it still uses the remote host's IP address The router then determines where to send the packet and inserts the new next hop MAC address, as required Figure 6-7 illustrates this process

suffer when projects are over budget, over time, and lacking resources But without sufficient training and ongoing support, you can almost guarantee the implementation will fail, however well the final design meets the initial specifications So remember:

5:

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Figure 6-7: A transmission using the default gateway In this example, host Einstein is trying to send a packet to host Darwin Two routers, Beethoven and Mozart, block their path Einstein determines that Darwin is a remote host, so he inserts Beethoven's MAC address into the packet and transmits Beethoven, upon receiving the packet, realizes that he must go through Mozart to get the packet to Darwin He therefore inserts Mozart's MAC address into the packet and transmits Mozart knows that Darwin should be reachable directly from his Ethernet interface, but he doesn't yet know Darwin's MAC address, so he ARPs for it Upon receiving Darwin's MAC address, Mozart inserts it into the packet and transmits the packet directly to Darwin When Darwin wishes to reply back to Einstein, the process is repeated in reverse Now that you have seen this entire process, let's try our hand at determining whether two hosts are on the same network In Figure 6-8, two hosts, Michelangelo and Renoir, are attempting to communicate Michelangelo has an IP address of 1721611, with a subnet mask of 25525500 Renoir has the IP address of 172165202, with a subnet mask of 2552552550 Can they communicate Take a second to work out the ANDing on your own before continuing

Figure 6-8: Two hosts attempting to communicate The answer is no Why Take a look at Figure 6-8 again If you perform the ANDing process, it looks as if Michelangelo will attempt to send the packet to a router because his network address is 17216800 and Renoir's is 1721650 Actually, the reverse is true Michelangelo has no way of knowing that Renoir is using a different subnet mask than he is He will assume that, because Renoir is using the same address block, he must be using the same subnet mask Therefore, when Michelangelo performs his ANDing, the result will match, and he will attempt to send it directly The unusual part is that Michelangelo's send operation will actually succeed because they really are on the same logical network However, when Renoir attempts to respond, he will fail because he will perform his own ANDing operation The result will be that they are on different networks Renoir will attempt to send the packet to a router, but the packet will never be delivered This process is shown in Figure 6-9

convert the binary to decimal, you should have the following as the network ID of each subnet:

out some of the system with them That way, you will have some readymade advocates who can help train other people because they really know the system and understand why certain decisions were made

Figure 6-9: Visual explanation of the failure The purpose of this final ANDing example is for you to realize that not only IP addresses but also subnet masks must match if hosts are on the same logical network If they do not match, the ANDing will be performed incorrectly, and the communication will fail

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Spend time with the users Formal training sessions are important,

Originally, IP addresses were divided into classes to allow companies of different sizes to use different numbers of addresses Table 6-1 lists the IP address classes For our purposes, we are concerned only with class A, B, and C addresses (Class D is discussed in the "Multicast Addressing" section, later in this chapter) Class A addresses support over 16 million hosts per network This class is obviously for very large networks (generally top-level ISPs) There are 126 valid class A networks, all of which were registered long ago Public IP addresses must be registered with the Internet Assigned Numbers Authority (IANA), the sanctioning body controlling the use of public or Internetaccessible IP addresses With a class A address, the MSB value in the first octet is always 0 This means that the smallest number you could have is 00000000 (0), and the largest is 01111111 (127) However, a few rules come into play in this case First, the class A network address of 0 is

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