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s you have learned, the concept of energy is extremely useful in mechanics The law of conservation of energy allows us to solve motion problems without knowing the forces in detail The same is true in the study of electrical interactions The work performed moving a charged particle in an electric field can result in the particle s gaining potential, or kinetic energy, or both Because this chapter investigates charges at rest, only changes in potential energy will be discussed



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Define electric potential difference Calculate potential difference from the work required to move a charge Describe how charges are distributed on solid and hollow conductors Solve problems pertaining to capacitance





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Recall the change in gravitational potential energy of a ball when it is lifted, as shown in Figure 21-5 Both the gravitational force, F, and the gravitational field, g F/m, point toward Earth If you lift a ball against the force of gravity, you do work on it, thereby increasing its potential energy The situation is similar with two unlike charges: they attract each other, and so you must do work to pull one charge away from the other When you do the work, you transfer energy to the charge where that energy is stored as potential energy The larger the test charge, the greater the increase in its potential energy, PE Although the force on the test charge depends on its magnitude, q , the electric field it experiences does not The electric field, E F/q , is the force per unit charge In a similar way, the electric potential difference, V, is defined as the work done moving a positive test charge between two points in an electric field divided by the magnitude of the test charge Electric Potential Difference V

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The difference in electrical potential is the ratio of the work needed to move a charge to the strength of that charge

Electric potential difference is measured in joules per coulomb One joule per coulomb is called a volt (J/C V) Consider the situation shown in Figure 21-6 on the next page The negative charge creates an electric field toward itself Suppose you place a small positive test charge in the field at position A It will experience a force in the direction of the field If you now move the test charge away from the negative charge to position B, as in Figure Ball 21-6a, you will have to exert a force, F, on a Increase in gravitational the charge Because the force that you exert g potential is in the same direction as the displacement, energy the work that you do on the test charge is positive Therefore, there also will be a positive change in the electric potential difference The change in potential difference does not depend on the magnitude of the test charge It depends only on the field and the displacement

Figure 21-5 Work is needed to move an object against the force of gravity (a) and against the electric force (b) In both cases, the potential energy of the object is increased

Answer (for Objective 73): is correct Swanky doesn t override equals(), so equals() returns true only when A both references are referring to the same object Similar to garbage collection questions, the best way to approach this question is to make a diagram of the reference variables, objects, connections between them, and when connections or references are lost B, C, D, E, and F are incorrect, loosely based on the above 26 Given:

Figure 21-6 Electric potential difference is determined by measuring the work per unit charge If you move unlike charges apart, you increase the electric potential difference (a) If you move unlike charges closer together, you reduce the electric potential difference (b)

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