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Together, these two observations make it obvious that the number of times the repeated part of the algorithm is executed is at most equal to the number of cards in the original deck It is worth noting in passing that this proof of termination does not depend on how the middle deck is split at each iteration It is allowed, for example, to always split it so that the lower deck is empty This is correct but inefficient A more efficient strategy is to always split the middle deck into two (as near as possible) equal parts, since this means that its size is (approximately) halved at each repetition We return to the issue of efficiency in 4 but, for the moment, correctness is our only concern (b) Conditional Correctness The second part of the proof of correctness is given the name conditional correctness1.



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// preceding section remains as it was in original source string [] nextOptions = new string [] {}; if (!stringIsNullOrEmpty(currentState)) { if ("Unassigned"==currentState) nextOptions = new string[] { "Unassigned", // allow leaving state unchanged "Assigned", "Rejected", }; if ("Approved"==currentState) nextOptions = new string[] { "Approved", // allow leaving state unchanged "Fixed", }; if ("Rejected"==currentState) nextOptions = new string[] { "Rejected", // allow leaving state unchanged }; if ("Fixed"==currentState) nextOptions = new string[] { "Fixed", // allow leaving state unchanged }; } else { // New Issue nextOptions = new string[] {"Unassigned"}; } // Rest of file stays as it was in original source





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Instantiating Generics Based on Reference Types Generics work slightly differently for reference types The first time a generic type is constructed with a reference type, the runtime creates a specialized generic type with object references substituted for type parameters in the CIL, not a specialized generic type based on the type parameter Each subsequent time a constructed type is instantiated with a reference type parameter, the runtime reuses the previously generated version of the generic type, even if the reference type is different from the first reference type

For example, suppose you have two reference types, a Customer class and an Order class, and you create an EntityDictionary of Customer types, like so:

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A proof of conditional correctness assumes that the execution of a program terminates and concentrates on establishing that its specification is met The properties we use to establish the conditional correctness of our searching algorithm have already been stated They are: (11) every card in the left deck precedes X in alphabetical order; (12) none of the cards in the right deck precedes X in alphabetical order; (13) the original deck may be retrieved by recombining the left, middle and right decks, in that order Note that these properties hold no matter how often the splitting process has been executed, and so we refer to them as invariants Note, also, that properties (I1)-(I3) generalize the properties (P1)-(P3) above Indeed, (II) and (PI) are identical, as are (12) and (P2) Properties (13) and (P3) are, however, different; they are the same only when the middle deck is empty.

EntityDictionary<Guid, Customer> customers;

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Prior to accessing this class, the runtime generates a specialized version of the EntityDictionary class that, instead of storing Customer as the specified data type, stores object references Suppose the next line of code creates an EntityDictionary of another reference type, called Order:

It is in this sense that (13) generalizes (P3) The invention of invariants is a crucial process in program construction Typically, as this example illustrates, invariants are generalizations of the required postcondition We use the principle of mathematical induction to prove that these three properties really are invariant Generally, the principle of mathematical induction is used to prove that some property Pn is true for all natural numbers n (The natural numbers are the whole numbers beginning at 0, thus 0,1, 2, 3 and so on The notation Tn' indicates that P is a function of n) In this case, n refers to the number of times the middle deck has been split and property P is property (II) and property (12) and property (13).

EntityDictionary<Guid, Order> orders = new EntityDictionary<Guid, Order>();

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