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The first proposition guarantees that at least one branch of the conditional statement can be chosen (recall that the square brackets around P => bl v b2 mean that the property is true in all states); the second and third propositions specify the correctness of the individual branches. Exercise 10.7. Introduce additional assertions into the following Hoare triples so that every assignment statement is bracketed by a precondition and a postcondition. Use the assignment axiom to verify the correctness of each assignment with respect to its precondition and postcondition.



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Lambda expressions themselves do not have type In fact, there is no concept of a lambda expression in the CLR Therefore, there are no members to call directly from a lambda expression The operator on a lambda expression will not compile, eliminating even the option of calls to object methods Given that a lambda expression does not have an intrinsic type, it cannot appear to the right of an is operator





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The regular expression contains a sequence of characters that you expect to nd in the string, and certain characters (parentheses, * + [ ] and one or two others) play special roles * signi es a repetition of zero or many of what went immediately before, so that < * matches a < followed by any number of spaces, including none + is similar, but insists on at least one occurrence Square brackets match any single character in the range de ned within, so that [A-Z]+ matches any sequence of at least one capital letter Parentheses demarcate a match that you wish to capture into a variable, so that ([A-Za-z]+) should return to you a word made of one or more alphabetics ( :)* repeatedly performs the matches within the parentheses without capturing the whole thing to a variable | speci es alternative matches ( <name>) matches a pattern that a later ${name} must match in the same way so that the use of quote in the following example ensures that an opening quotation is matched with the same kind of closing mark This regular expression:

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// ERROR: The first operand of an 'is' or 'as' // operator may not be a lambda expression or // anonymous method bool boolean = ((int x) => x) is Func<int, int>; // ERROR: Lambda expression is not compatible with // Func<int, bool> type Func<int, bool> expression = ((int x) => x);

(a) { mxn = p }

Although there is no type on the lambda expression on its own, once assigned or cast, the lambda expression takes on a type Therefore, it is common for developers to informally refer to the type of the lambda expression concerning type compatibility, for example A lambda expression cannot be assigned to an implicitly typed local variable since the compiler does not know what type to make the variable given that lambda expressions do not have type

matches, for example:

// ERROR: Cannot assign lambda expression to an // implicitly typed local variable var thing = (x => x);

{ 0 < w i A O ^ n A gcd(m,n)=C }

TABLE 121: Lambda Expression Notes and Examples (Continued)

// ERROR: Control cannot leave the body of an // anonymous method or lambda expression string[] args; Func<string> expression; switch(args[0]) { case "/File": expression = () => { if (!FileExists(args[1])) { break; } // return args[1]; }; // } // ERROR: The name 'first' does not // exist in the current context Func<int, int, bool> expression = (first, second) => first > second; first++;

Exercise 10.8. Rather than assign the absolute value of A: to a new variable y as we did above, it may be required to update x to its absolute value. To specify such an update operation it is necessary to use a ghost variable. The program segment complete with precondition and postcondition is shown below, variable X being the ghost variable.

as illustrated in Figure 11-19

C# does not allow jump statements (break, goto, continue) inside anonymous functions if the target is outside the lambda expression Similarly, you cannot target a jump statement from outside the lambda expression (or anonymous methods) into the lambda expression

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