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supporting axial loads In certain machines, two thrust bearings are used because axial loadings can arise in both directions, and the rotor must be located axially as precisely and rigidly as possible The greatest axial stiffness is realized if the two bearings are loaded against one another at the design condition Kg = 069 as shown in Figure 760 The design load, W* is given in Figure 761 and 762 and the stiffness provided is twice that of a single isolated thrust bearing under the same load When loaded, the pressure in each of the two bearings may be different, and the resultant ultimate load is 25% higher than the design load This value can be slightly increased by light preloading by utilizing an end float However, this can result in a higher gas flow, lower stiffness and a pneumatic hammer Sometimes, two unequal thrust bearings may be used The ultimate load in both directions = 125 W*, where W* is the design load of a single bearing at Kg = 069 Therefore, the equivalent load is given by



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The binary system The numbers we use in daily life consist of ten digits. The digit 1 represents a single thing, such as a pebble. 2 is a pebble next to it. Add another pebble and you can represent their quantity with the symbol 3. The digits are just symbols that stand in for a particular quantity of pebbles. 0 is special since it represents no pebbles. Nine pebbles are the most we can represent with a single digit. What happens when we add another pebble We get the symbol sequence 10. Each digit s value is a ected by its position in the sequence. The right-most digit is in the ones place and is worth its face value. The next digit to the left is in the tens place, where a 1 stands for ten pebbles, 2 is twenty, and so forth. This system is known as the decimal system, or base-10. Each place value is ten times the place value to its right. To make the obvious complicated, the quantity represented by the sequence of digits is calculated by: n 1 X dp 10 p q10





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05 069 load 10 h*

where: q10 is the quantity represented by the sequence of base-10 digits; n is the number of digits in the sequence; p is the place number of a digit, from zero at the right to n 1 at the left; d is the quantity represented by the digit at position p. Binary coding is exactly the same but with only two digits, 0 and 1: n 1 X q2 dp 2p

Ultimate load in both directions = 125 W* where W * is the design load of a single bearing at Kg = 069 W* Stiffness kA = 288 at central position h*

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120 100 = 128 lbf 570 N 125 75 On referring to Figure 761, it can be concluded that an annular thrust bearing of a 3 in outside diameter and a 1 in inside diameter supplied at 100 lbf/in2 can carry a load of 195 lbf at the design clearance of 00005 in The load value is obtained from the intersection of the inside diameter and the outside diameter The airflow is determined in a similar manner The airflow at a 100 lbf/in2 gauge would be 074 scfm and at a 75 lbf/in2 gauge would be 074 0625 scfm = 0463 scfm (00131 m3/min) For this example, the annular air thrust bearings with rings of jets are chosen because the shaft is assumed to go through the bearings From Figure 762, it is seen that, in certain cases, a central feed hole arrangement can be used

So the binary sequence: 1101011 represents the quantity: 1 26 1 25 0 24 1 23 0 22 1 21 1 20 64 32 8 2 1 107 From Edwin Wise, Hands-On AI with Java (McGraw-Hill, 2004)

Fig 760: Combination of two thrust bearings [3]

Fig 761: The general performance of annular air thrust bearings with a ring of jets [3]

Table 7-1 Four-bit patterns and labeling Binary 0000 0001 0010 0011 0100 0101 0110 0111 1000 1001 1010 1011 1100 1101 1110 1111 Label 0 1 2 3 4 5 6 7 8 9 A B C D E F

Fig 762: The general performance of air thrust bearings with a central feed hole and a circular pocket [3]

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