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Steps to convert word document to PDF programmatically :
Steps to convert word document to PDF programmatically :

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If any of the extra bytes following s1 that are needed to copy s2 are in use by any other object, then all of s1 and its appended s2 will be copied to some other free section of memory.

The isstraight () function, the isFlush () function,andthe isStraightFlush() function are also tricky. Here is the i sF lus h ( ) function: int Hand: :isFlush() 1 for (int i = 1; i < size; i++) if (cards[i].suit!= cards[O].suit - > return 0; return 1;

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Free source code and tutorials for Software developers and Architects.; Updated: 9 Mar 2017.

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Dec 19, 2018 · Let's learn how to convert a Word document to a PDF programmatically in C# without Microsoft Office or interop. Syncfusion Word library ...

This compares the sui t of each of the second through fifth cards (card [ l] through card [ 41). If any of these are not thesame, then we know immediately that the hand is not a flush and can return 0. If the loop terminates naturally, then all four pairs match and 1 is returned. Here is the Deck class: #include "Rand0m.h" #include 'Hand.h" class Deck { public: Deck(); void shuffle(); void deal(Hand&, private: unsigned top; Card cards[52]; Random random; 1;

strcat(s1,s2)

unsigned =5>;

CHAP. 8]

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Online C# Tutorial for Converting Word to PDF (.pdf) Document.

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Word.Application word = new Microsoft.Office.Interop.Word.Application(); // C# doesn't have optional arguments so we'll need a dummy value ...

Now, here is where we start to get into the meat and potatoes of the XMLHttpRequest object. This is the method you use to open a connection to a particular file on the server. It is where you pass in the method to open a file (GET or POST), as well as define how the file is to be opened. Keep in mind that not all of the arguments in this function are required and can be customized depending on the situation.

It uses the Random class in its shu f f 1 e ( ) function. Note that the random object is declared as a private member since it is used only by another member function: void 1 Deck::deal(Hand& hand, unsigned size=5)

for (int i = 0; i < size; i++) hand.cards[i] = cards[top++]; hand.sort();

EXAMPLE 8.18 The Second String Concatenation Function strncat()

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The top member always locates the top of the deck; i.e., the next card to be dealt. So the deal ( ) function copies the top five cards off the deck into the hand's cards array. Then it sorts the hand. The Deck's constructor initializes all 52 cards in the deck, int the order two of clubs, three of clubs, four of clubs,..., ace of spades: Deck::Deck() 1 for (int i = 0; i < 52; i++) { cards[i] .rank = Rank(i%l3); cards[i].suit= Suit(i/l3); 1 top = 0;

This program traces calls strncat(s1,s2,n): #include <cstring> #include <iostream> using namespace std; int main() { // test-driver for the strncat() function: char s1[] = "ABCDEFG"; char s2[] = "XYZ"; cout << "Before strncat(s1,s2,2):\n"; cout << "\ts1 = [" << s1 << "], length = " cout << "\ts2 = [" << s2 << "], length = " strncat(s1,s2,2); cout << "After strncat(s1,s2,2):\n"; cout << "\ts1 = [" << s1 << "], length = " cout << "\ts2 = [" << s2 << "], length = " } Before strncat(s1,s2,2): s1 = [ABCDEFG], length = 7 s2 = [XYZ], length = 3 After strncat(s1,s2,2): s1 = [ABCDEFGXY], length = 9 s2 = [XYZ], length = 3 The call strncat(s1,s2,2) appends XY onto the end of s1. The effect can be visualized as shown here. s1 Since s2 has length 3, strncat(s1,s2,2) copies 2 bytes overwriting the NUL character of s1 and the byte that follows it. Then it puts the NUL character in the next byte to complete the C-string s1. This increases its length to 9. (If either of the extra 2 bytes had been in use by some other object, then the entire 10 characters ABCDEFGXY would have been written in s2 some other free part of memory.)

So if hands are dealt without shuffling first, the first hand would be the straight flush of two through six of clubs. Finally, here is the shu f f 1 e ( ) function: void Deck::shuffle() for (int i = 0; i < 52; i++) int j = random.integer(O, Card c = cards[i]; cards[i] = cards[j]; cards[j] = c; > top = 0; { 51); // do 52 random swaps

It swaps the cards in each of the 52 elements with the card in a randomly selected element of the deck s cards array The implementations of the other functions are left as exercises. (See Problem 11.18.) 11.15

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Aug 1, 2013 · Demonstrates using Word Automation Services in an app, which is then wrapped with a custom REST service.

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